x^2+4x+3=x+1

Solution for x^2+4x+3=x+1 equation:

Simplifying
x2 + 4x + 3 = x + 1

Reorder the terms:
3 + 4x + x2 = x + 1

Reorder the terms:
3 + 4x + x2 = 1 + x

Solving
3 + 4x + x2 = 1 + x

Solving for variable 'x'.

Reorder the terms:
3 + -1 + 4x + -1x + x2 = 1 + x + -1 + -1x

Combine like terms: 3 + -1 = 2
2 + 4x + -1x + x2 = 1 + x + -1 + -1x

Combine like terms: 4x + -1x = 3x
2 + 3x + x2 = 1 + x + -1 + -1x

Reorder the terms:
2 + 3x + x2 = 1 + -1 + x + -1x

Combine like terms: 1 + -1 = 0
2 + 3x + x2 = 0 + x + -1x
2 + 3x + x2 = x + -1x

Combine like terms: x + -1x = 0
2 + 3x + x2 = 0

Factor a trinomial.
(2 + x)(1 + x) = 0

Subproblem 1
Set the factor '(2 + x)' equal to zero and attempt to solve:

Simplifying
2 + x = 0

Solving
2 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2

Combine like terms: 0 + -2 = -2
x = -2

Simplifying
x = -2
Subproblem 2
Set the factor '(1 + x)' equal to zero and attempt to solve:

Simplifying
1 + x = 0

Solving
1 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + x = 0 + -1
x = 0 + -1

Combine like terms: 0 + -1 = -1
x = -1

Simplifying
x = -1
Solution
x = {-2, -1}